How to optimize the code for 10 power 5 output

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How to optimize the code for 10 power 5 output



Please help me to find out how to optimize this code for 10 to the power 5 output in java. It's show time limit error. Even i try to use HashMap in place of DP array. I tried all the method which i know to optimize this. For bigger output i used long as datatype.


public static void main(String args) throws Exception {
Scanner s = new Scanner(System.in);
int t = s.nextInt();
HashMap<Long, Long> hash = new HashMap<Long, Long>();
for (int i = 0; i < t; i++) {
int n = s.nextInt();
int a = s.nextInt();
int b = s.nextInt();
long val = Long.MAX_VALUE;
if (a == b) {
if (n % 2 == 0) {
int ans = (n / 2) * (n / 2);
val = (a * ans) + (b * ans);
} else {
int ans = n / 2;
val = (a * (ans * ans)) + (b * ((ans + 1) * (ans + 1)));
}
} else {
for (long j = 0; j <= n; j++) {
if (hash.containsKey(j) && hash.containsKey(n - j)) {
long cal = (a * hash.get(j)) + (b * hash.get(n - j));
if (val > cal) {
val = cal;
}
} else {
if (!hash.containsKey(j)) {
hash.put(j, j * j);
}
if (!hash.containsKey(n - j)) {
hash.put(n - j, (n - j) * (n - j));
}
long cal = (a * hash.get(j)) + (b * hash.get(n - j));
if (val > cal) {
val = cal;
}
}
}
}
System.out.println(val);
}
}





javascript !== java
– Nina Scholz
7 hours ago


javascript !== java





what on earth are you trying to do?
– Gyro Gearless
6 hours ago





It looks like the search for the minimum of a*j²+b*(n-j)² for 0<=j<=n.
– Ralf Renz
6 hours ago









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