print number having digit 3 or 6 from 1 to 1000.like 3 ,6,13,16…996,

Here is my code. When the value of the number is less than 100, output is correct but when the value of number is 1000.output is wrong

import java.util.*;
public class Test {
public static void main(String args) {
int i,x,y,z,num;
int number=1;

for(;number<1000;number++) {
i=number;
while (i > 0) {
z=i%10; //System.out.println( "digit="+z);
if(((z%3==0)&&(z%9!=0)&&(z!=0))||(z%6==0)&&(z!=0)) //condition for divisiblity by 3 or 6 and not by 9
{
System.out.println( "number="+number);
break;
}
i = i / 10;
}
}
}
}


if

z==3 || z==6

2 Answers
2

This is much shorter and makes a whole lot more sense.

for(int i = 0; i < 1000; i++){
String str = Integer.toString(i);

for(int j = 0; j < str.length(); j++){
if(str.charAt(j) == '3' || str.charAt(j) == '6')
System.out.println("nuber = "+ i);
}
}


String.contains

Your code works just fine, the only thing missing is your loop is till 999.

Aslo, In Java 8, you can simply do :

IntStream.range(1,1001).mapToObj(p->Integer.toString(p)).filter(p->p.contains("3")||p.contains("6")).forEach(System.out::println);


Output:

3
6
13
16
.
.
993
996


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